Gravitational Attraction
What would happen if two people out in space a few meters apart, abandoned by their spacecraft, decided to wait until gravity pulled them together? My initial thought was that …
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Going back a few years I published an article simplifying the calculations for atmospheric greenhouse gas effects for undergraduate non-science majors,
Blais, B. (2003). Teaching energy balance using round numbers. Physics education, 38(6), 519.
I recently came across another article which does a similar thing, but using slightly different notation and terminology,
LoPresto, M. C. (2013). Adding albedo and atmospheres. The Physics Teacher, 51(3), 152-153.
In the spirit of reproducibility I wanted to see if I could connect LoPresto's results with mine.
In my method, the amount of energy entering the Earth system is the round number where is the distance from the sun in astronomical units (AU). In these units, for the Earth. The temperature of the surface, or any atmospheric layer, is related to the energy output of that layer, derived to be We look at a simple 1-layer model, where the short-wavelength albedo is and the atmosphere absorbs some fraction, , of the long-wavelength radiation.
we get energy balance equations of
which leads to solutions for the energy emitted from the surface and the layer 1, as well as the corresponding temperatures,
We can check a few extreme cases, like (no atmosphere), and an infrared-opaque atmosphere, ,
Using the numbers from LoPresto, M. C. (2013), where the albedo () is measured but the long-wavelength radiation fraction of absorption () is inferred^[LoPresto uses values for the properties of the atmosphere in their table, but admits there is a lot of variation. I prefer to infer the values from the temperatures, and discuss whether it makes sense.], we get
Albedo | T Obs. [K] | Distance from Sun [AU] | T (no atm) [K] | T (γ=0.3) [K] | γ (best fit) | |
---|---|---|---|---|---|---|
Mercury | 0.119 | 400 | 0.39 | 434.2 | 452.2 | -0.776 |
Venus | 0.75 | 737 | 0.72 | 233.2 | 242.9 | 1.98 |
Earth | 0.306 | 288 | 1 | 255.4 | 266 | 0.762 |
Mars | 0.25 | 225 | 1.52 | 211.2 | 220 | 0.446 |
Jupiter | 0.343 | 124 | 5.2 | 110.5 | 115.1 | 0.739 |
Saturn | 0.342 | 97 | 9.58 | 81.4 | 84.8 | 1.006 |
Uranus | 0.3 | 58 | 19.22 | 58.4 | 60.8 | -0.054 |
Neptune | 0.29 | 59 | 30.07 | 46.8 | 48.8 | 1.205 |
There are several things to note here. If we interpret as the fraction absorbed, both and are physically impossible. The former indicates that there is no atmosphere and we must be within uncertainties in the albedo or observed temperature. The latter is something we can address, by modifying the model. This is done by deriving the equations used in LoPresto, M. C. (2013).
From the paper,
LoPresto, M. C. (2013). Adding albedo and atmospheres. The Physics Teacher, 51(3), 152-153.
we are given the result from a multi-layer model atmosphere. Their result for the case without an atmosphere is which we call for effective radiative temperature.^[LoPresto calls it simply which we find unclear.]. This is the same as our case, They then include a greenhouse, and derive the temperature to be which is equivalent to our case above with . They then quote a result, without derivation, of which their previous result is a special case (). The value is called the "total extinction thickness" and is the number of layers that completely absorb infrared radiation (i.e. long wavelength). So there must be some connection between my and their .
To derive their result, we add more layers to the original model, and assume that every layer absorbs 100% of the radiation entering it from other layers.
The energy balance equations for such layers is,
You can confirm that this works for the model shown. Notice that there is an asymmetry in the equations, with the surface-layer and the top-layer equations a little different from the others.
Solving from the top layer (last equation) down to the surface we get From the first balance equation we
Our final result for the energy output of the surface in the multi-layer model is,
Where the last step is the result from LoPresto, where it is clear that the number of layers, , is equivalent to their "total extinction thickness", .
Connecting my to LoPresto's we get
or We can then reproduce the table above
Albedo | T Obs. [K] | Distance from Sun [AU] | T (no atm) [K] | γ (best fit) | τ (best fit) | T (best fit) | |
---|---|---|---|---|---|---|---|
Mercury | 0.119 | 400 | 0.39 | 434.2 | -0.776 | -0.28 | 400 |
Venus | 0.75 | 737 | 0.72 | 233.2 | 1.98 | 98.729 | 736.9 |
Earth | 0.306 | 288 | 1 | 255.4 | 0.762 | 0.616 | 288 |
Mars | 0.25 | 225 | 1.52 | 211.2 | 0.446 | 0.287 | 225 |
Jupiter | 0.343 | 124 | 5.2 | 110.5 | 0.739 | 0.586 | 124 |
Saturn | 0.342 | 97 | 9.58 | 81.4 | 1.006 | 1.013 | 97 |
Uranus | 0.3 | 58 | 19.22 | 58.4 | -0.054 | -0.026 | 58 |
Neptune | 0.29 | 59 | 30.07 | 46.8 | 1.205 | 1.516 | 58.9 |
The interpretation of, say, Venus's (100 effective layers!) is much easier using this result rather than the physically unreasonable . In teaching this concept to students again, I may sketch the derivation, and then quote the result:
which has a reasonably intuitive simple form. I imagine there may be other useful comparisons to make.